If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords

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If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, AE⋅EC=DE⋅EB .

Posted By Simphy / Apr-13-2022

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