If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords
If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, AE⋅EC=DE⋅EB .
